Final answer:
To calculate the grams of AlCl3 in one mole, the molar mass of AlCl3 is 133.33 g/mol. In a 1.5 M solution, there would be 135.12 grams of H3C6H5O7 per liter. For one mole of baking soda, 188.18 grams of potassium bitartrate are needed. A double-acting baking powder releases carbon dioxide gas twice during the baking process.
Step-by-step explanation:
To calculate the grams of AlCl3 in one mole, we need to determine the molar mass of AlCl3. The molar mass of AlCl3 is 133.33 g/mol. Therefore, in one mole, there are 133.33 grams of AlCl3.
To calculate the grams of H3C6H5O7 (lactic acid) in one liter of a 1.5 M solution, we need to use the formula: grams = moles x molar mass. The molar mass of H3C6H5O7 is 90.08 g/mol. In a 1.5 M solution, there are 1.5 moles of H3C6H5O7 per liter. Therefore, in one liter of the solution, there would be 135.12 grams of H3C6H5O7.
To determine how many grams of potassium bitartrate are needed for one mole of baking soda, we need to use the mole ratio from the balanced chemical equation. The balanced equation is: 1 KHC4H4O6 : 1 NaHCO3. The molar mass of KHC4H4O6 is 188.18 g/mol. Therefore, 188.18 grams of potassium bitartrate are needed for one mole of baking soda.
A double-acting baking powder works by releasing carbon dioxide gas twice during the baking process. The first release occurs when the baking powder is mixed with a liquid, and the second release occurs when it is heated in the oven. This creates additional bubbles in the batter or dough, resulting in a lighter and fluffier final product.