Question

Given that RS=18 and QR=6, identify the length of PS¯¯¯¯¯.PS=6√12PS=12√3PS=8√3PS = 18

Answer 1

We have to use the sine to find PS due to the fact that the triangle PRS is a right triangle.

Then:

`\begin{gathered} cos45\text{ = }(RS)/(PS) \\ (√(2))/(2)=\text{ }(18)/(PS) \\ √(2)\text{ = }(36)/(PS) \\ PS=\text{ }(36)/(√(2)) \\ PS=\text{ }(36√(2))/(2) \\ PS=\text{ 18}√(2) \\ \\ \end{gathered}`