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Which of these molecules will have stronger London Dispersion forces: A) benzene (C6H6) B)glycerol (C3H8O3) Explain your answer.

User Yunti
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Final answer:

The larger the molecule, the stronger the London Dispersion forces. Benzene (C6H6) will have weaker London Dispersion forces compared to glycerol (C3H8O3).

Step-by-step explanation:

All of these compounds are nonpolar and only have London dispersion forces: the larger the molecule, the larger the dispersion forces and the higher the boiling point. The ordering from lowest to highest boiling point is therefore C₂H₆ < C₃H₈ < C₄H₁₀.

User Roger Heathcote
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