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The centripetal force F exerted on a passenger by a spinning amusement park ride is related to the number of seconds s the ride takes to complete one revolution by the equation F = 1552. What is the centripetal force exerted on a passenger when it takes 12 seconds for the ride to complete one revolution? (Force is measured in Newtons)

a) 129.33 N
b) 144.67 N
c) 167.33 N
d) 172.67 N

1 Answer

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Final answer:

The centripetal force exerted on a passenger when the amusement park ride takes 12 seconds to complete one revolution is calculated using the given equation F = 1552/s and is found to be 129.33 Newtons.

Step-by-step explanation:

The question is asking to calculate the centripetal force exerted on a passenger by a spinning amusement park ride, given the time it takes for the ride to complete one revolution. According to the question, the centripetal force F can be determined by the equation F = 1552/s, where s is the number of seconds for one revolution. When it takes 12 seconds for the ride to complete one revolution, we can calculate the force as:

F = 1552 / 12 = 129.33 N

Thus, the centripetal force exerted on a passenger when it takes 12 seconds for the ride to complete one revolution is 129.33 Newtons.

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