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A simple random sample from a population with a normal distribution of 100 body temperatures has x=98.80 degrees F and s=0.67 degrees F. Construct ​80% confidence interval estimate of the standard deviation of body temperature of all healthy humans.

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Final answer:

To construct an 80% confidence interval estimate of the standard deviation of body temperature of all healthy humans, use the formula and plug in the given values.

Step-by-step explanation:

To construct an 80% confidence interval estimate of the standard deviation of body temperature of all healthy humans, we can use the formula:

Lower Limit: S = √((n-1) * s² / chi-square(1-α/2, n-1))

Upper Limit: S = √((n-1) * s² / chi-square(α/2, n-1))

where n is the sample size, s is the sample standard deviation, and α is the level of significance. In this case, n=100, s=0.67, and α=0.2 (since we want an 80% confidence interval).

Plugging in the values, we obtain:

Lower Limit: S = √((100-1) * 0.67² / chi-square(1-0.2/2, 100-1))

Upper Limit: S = √((100-1) * 0.67² / chi-square(0.2/2, 100-1))

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