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The length of a rectangle is seven less than twice its width if the perimeter is at most 58 inches, then determine the greatest possible measure of the length of the rectangle.

User Sam Dolan
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1 Answer

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Final answer:

By representing the width with w and creating an inequality from the given information, the width w is found to be at most 12 inches. Substituting this into the length formula, the greatest possible measure of the length of the rectangle is determined to be 17 inches.

Step-by-step explanation:

To find the greatest possible measure of the length of the rectangle, let's denote the width as w inches. According to the problem, the length l is seven less than twice its width, so l = 2w - 7. The perimeter P of a rectangle is given by P = 2l + 2w. Since the perimeter is at most 58 inches, we have 2(2w - 7) + 2w ≤ 58. Simplifying this inequality:

  • 4w - 14 + 2w ≤ 58
  • 6w - 14 ≤ 58
  • 6w ≤ 72
  • w ≤ 12

Therefore, the width w is at most 12 inches. To find the greatest possible length, substitute w = 12 into the length formula:

  • l = 2(12) - 7
  • l = 24 - 7
  • l = 17

So, the greatest possible length of the rectangle is 17 inches.

User Sharpling
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