Question

Two capacitors having values of 10 μF each are connected in parallel and then hooked up to a 9.0 V battery. How much energy must the battery supply to charge the capacitors?Group of answer choices9.0x10-5 J8.1x10-4 J2.3x10-5 J1.6x10-3 J2.0x10-4 J

Answer 1

Given,

Two capacitors having values of 10 μF each are connected in parallel.

They are then connected to a 9.0 V battery.

The equivalent capacitance is:

`C=10\mu F+10\mu F=20\mu F`

Thus the energy is equal to,

`\begin{gathered} U=(1)/(2)CV^2 \\ \Rightarrow U=(1)/(2)*(20*10^(-6))*9^2 \\ \Rightarrow U=8.1*10^(-4)J \end{gathered}`

The answer is

`8.1*10^(-4)J`