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An airplane takes off from the airport. From a full stop, it reaches a velocity of 67.0 m/s after traveling a distance of 925 m. What was the plane’s acceleration?

A: 0.65 m/s²
B: 1.45 m/s²
C: 0.72 m/s²
D: 1.20 m/s²

User Sanjeewa
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1 Answer

3 votes

Final answer:

To calculate the acceleration of the airplane, we use the kinematic equation vf2 = vi2 + 2ad, with vi as 0 m/s since it starts from rest. After plugging in the values and simplifying, the acceleration calculation doesn't match any of the available options, suggesting there might be a mistake in the question or options provided.

Step-by-step explanation:

To find the airplane's acceleration, we can use the kinematic equation that relates initial velocity (vi), final velocity (vf), acceleration (a), and distance (d):

vf2 = vi2 + 2ad

Since the plane starts from a full stop, vi = 0 m/s.

Plugging in the given values:

67.02 = 0 + 2a(925)

Upon calculating:

a = ´(67.02) / (2 × 925)

a = 2.4225...

Since the options provided don't include this value, we may need to consider whether there's a calculation error or if the question might contain a mistake.

User Muhammad Saad
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