Question

If a 13.2 g ring is heated using 150.0 calories, its temperature rises 27.9°C.

Calculate the specific heat capacity of the ring.

Answer 1

To find the specific heat capacity of the ring, the formula q = mcΔT is used. With provided values, the specific heat capacity is calculated to be approximately 0.408 cal/g°C.

Step-by-step explanation:

To calculate the specific heat capacity of the ring, we can use the formula q = mcΔT, where q is the heat energy in calories, m is the mass in grams, c is the specific heat capacity in calories/g°C, and ΔT is the change in temperature in degrees Celsius (°C).

In this case, the student has given us the following values to work with:

• Heat energy (q) = 150.0 calories
• Mass (m) = 13.2 g
• Temperature increase (ΔT) = 27.9°C

We need to find the specific heat capacity (c). Rearranging the formula to solve for c, we get:

c = q / (mΔT)

Now we can plug in the values:

c = 150.0 calories / (13.2 g × 27.9°C)

Let's calculate:

c = 150.0 calories / (367.68 g°C)

c = 0.408 cal/g°C

Therefore, the specific heat capacity of the ring is approximately 0.408 cal/g°C.