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Write the standard form of the equation of the line that passes through (-2, -3) and (2, -5).

A. 2x + y = -7
B. x + 2y = -8
C. 2x - y = -1
D. x - 2y = -8

User Sesser
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1 Answer

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Final answer:

The standard form of the equation of the line passing through (-2,-3) and (2,-5) is 2x - y = 4.

Step-by-step explanation:

To find the standard form of the equation of a line, we need to determine the values of A, B, and C in the equation Ax + By = C. We can do this by using the given points (-2,-3) and (2,-5).

Step 1: Find the slope (m) using the formula m = (y2 - y1) / (x2 - x1). In this case, the slope is (-5 - (-3)) / (2 - (-2)) = -2/4 = -1/2.

Step 2: Use the slope-intercept form of the equation y = mx + b to find the y-intercept (b). Using one of the given points, (-2,-3), we can substitute the coordinates into the equation to find b. -3 = (-1/2)(-2) + b. Solving for b, we get b = -2.

Step 3: Substitute the slope (m) and y-intercept (b) into the standard form equation Ax + By = C. Plugging in the values, we have -1/2x + y = -2.

Step 4: Multiply both sides of the equation by 2 to get rid of the fraction, and rearrange to put the equation in standard form. The final answer is 2x - y = 4.

User Lionel Chan
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