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A person pushes a 70 Kg object with a force of 250 N. Assuming the friction force is 35 N, what is the acceleration experienced by the object?

a) 1.5 m/s²
b) 2.5 m/s²
c) 3.5 m/s²
d) 4.5 m/s²

User Zomboble
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1 Answer

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Final answer:

The acceleration experienced by a 70 Kg object pushed with a force of 250 N, with a friction force of 35 N, is closest to 3.5 m/s² according to Newton's Second Law of Motion.

Step-by-step explanation:

The subject of this question is Physics, and it relates to the concept of Newton's Second Law of Motion, which is often covered at the High School level. To find the acceleration experienced by the object, we apply Newton's Second Law: № = ma, where № is the net force, m is the mass, and a is the acceleration. The net force can be calculated by subtracting the friction force from the applied force. So the net force is 250 N - 35 N = 215 N. Using the formula a = №/m, the acceleration is 215 N / 70 kg = 3.07 m/s². This value is not exactly one of the provided options, but it is closest to option c) 3.5 m/s², which is likely the expected answer considering typical rounding in physics problems.

User Colecmc
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