Final answer:
To display the first 100 pentagonal numbers in Python, create a function 'getPentagonalNumber' to calculate the numbers and a main function to print them in the specified format with 10 numbers per line.
Step-by-step explanation:
The subject of the question is to work with pentagonal numbers, which are figures in mathematics defined by the formula for any nth term: n(3n-1)/2.
To generate and display the first 100 pentagonal numbers in Python, we should write a function getPentagonalNumber(n) that returns the nth pentagonal number, and a main function that calls this function for the first 100 terms, formatting the output in the requested manner.
A simple Python function to calculate the nth pentagonal number could be written as:
def getPentagonalNumber(n):
return n*(3*n-1)//2
The main function that uses getPentagonalNumber to print the first 100 pentagonal numbers, organizing 10 numbers per line and using the format function for formatting, may look like this:
def main():
for i in range(1, 101):
# Call the pentagonal number function and format the output
print('{:<5}'.format(getPentagonalNumber(i)), end=' ')
# Every 10 numbers, print a new line
if i % 10 == 0:
print()
This program will print the first 100 pentagonal numbers in a neat, readable format, with properly-aligned columns.