Question

H(-9,3) and A (8,-3)Find the midpoints?

Answer 1

The given points are

`\begin{gathered} H(-9,3) \\ A(8,-3) \end{gathered}`

We are asked to find the midpoint.

Recall that the midpoint formula is given by

`(x,y)=(x_1+x_2)/(2),(y_1+y_2)/(2)`

We have

`\begin{gathered} x_1=-9 \\ x_2=8 \\ y_1=3 \\ y_2=-3 \end{gathered}`

Substitute the given values into the midpoint formula.

`\begin{gathered} (x,y)=(-9+8)/(2),(3-3)/(2) \\ (x,y)=(-1)/(2),(0)/(2) \\ (x,y)=(-(1)/(2),0) \end{gathered}`

Therefore, the midpoint of H(-9, 3) and A (8, -3) is found to be

`(x,y)=(-(1)/(2),0)`

Or it can also be written in the decimal notation as

`(x,y)=(-0.5,0)`