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F(x) =S4-x²,(2x+1,x < 0X>0

User Danil Shaykhutdinov
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1 Answer

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12 votes

We start by graphing f(x) = (1/2)x+3.

This is a line with y-intercept y(0)=3.

We calculate another point so we can draw the line that goes through both points.

For example, when x=-6, y=0.

So we have the points (0,3) and (-6,0) that belongs to the line.

We can use them to draw the line:

We can now draw g(x).

This function is defined in parts: one function for x<=0 and other for x>0.

When x<=0, the function is g(x)=4-x^2.

This is a quadratic function. When x=0, y=4, so we know the y-intercept.

When x=2, y=0, so we now know the x-intercept.

We can aproximate the function with these two points:

F(x) =S4-x²,(2x+1,x < 0X>0-example-1
User Chris Jefferson
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