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Convert the following program from machine language into ARM assembly language. The numbers on the left are the instruction addresses in memory, and the numbers on the right give the instruction at that address

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Final answer:

This program converts machine language into ARM assembly language by performing arithmetic operations on values stored in memory addresses.

Step-by-step explanation:

  1. Load the value at address 100 into register R0.
  2. Increment the value in R0 by 1 and store the result back in R0.
  3. Store the value in R0 at address 104.
  4. Load the value at address 108 into register R1.
  5. Add the value in R0 to the value in R1 and store the result in R2.
  6. Store the value in R2 at address 112.
  7. Load the value at address 116 into register R3.
  8. Subtract the value in R2 from the value in R3 and store the result in R4.
  9. Store the value in R4 at address 120.
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