Final answer:
To right-shift a 16-bit binary word in the LC-3 ISA, you would use a series of ADD and AND instructions to move all the bits one position to the right and ensure the leftmost bit is set to 0.
Step-by-step explanation:
To right-shift a 16-bit binary word in the LC-3 Instruction Set Architecture (ISA), you would use the bitwise logical shift operation. This involves moving all the bits in the binary word one position to the right, with the far left bit receiving a value of 0 in a logical shift. In the LC-3, there isn't a single instruction for logical shifting; instead, you would perform a series of operations utilizing the ADD and AND instructions to effectively create a right-shift operation. For example, to right-shift by one position, you would need to AND the binary word with a bit mask that clears the leftmost bit (to ensure it becomes 0) and then ADD the binary word to itself, effectively dividing the value by two and accomplishing the right shift.
This operation can be performed using the LC-3 instruction called 'SHIFT' in combination with the 'RSH' option. The SHIFT instruction takes two operands - the source register containing the binary word and the destination register where the result will be stored. The RSH option specifies a right shift operation. The LC-3 hardware will perform the right shift operation and store the result in the destination register.