Final answer:
The x86 instruction SUB CL, [BX+DI+0x200] includes a subtraction where the machine code starts with 001010, followed by the MOD-REG-RM byte, and a 16-bit displacement for the 200h offset. Exact encoding varies by the processor's ISA.
Step-by-step explanation:
The instruction format diagram for the x86 assembly language command SUB CL, [BX+DI+0x200] represents subtraction of a byte at a memory location pointed to by BX and DI registers offset by 200h from the CL register. The machine code for the subtraction operation SUB can start with 001010, as you indicated that the opcodes for SUB start with those bits. Then, following the x86 instruction encoding:
- The MOD-REG-RM byte indicates a mod value that suggests using BX and DI with an offset.
- The SIB byte (Scale-Index-Base) would follow if needed, but it is not used for this particular instruction format.
- Finally, a disp16 (displacement of 16 bits) needs to be added to represent the 200h offset.
However, we would need to check the Instruction Set Architecture documentation to write down the exact binary sequence, as it can vary based on the specific processor's ISA.
The opcode for the SUB instruction is 001010 (in binary) or 0A (in hexadecimal). The first part of the opcode indicates the instruction type and the second part specifies the operands.
Machine Code
The machine code for the instruction SUB CL, [BX][DI]200h is:
10001001 11111011 10000000 00000000 00100000
The first byte is the opcode, followed by the mod-reg-r/m byte, the SIB byte, the displacement, and the immediate data.