Final answer:
To write a Java program that divides each n-digit integer into three smaller integers of n/3 digits using a modified version of Algorithm 2.9, you can implement a divide and conquer strategy by recursively dividing the input integer and multiplying the smaller parts.
Step-by-step explanation:
To write a Java program that uses a modified version of Algorithm 2.9 (Large Integer Multiplication) to divide each n-digit integer into three smaller integers of n/3 digits, you can implement a divide and conquer strategy.
The program can recursively divide the input integer into three parts, and then multiply the smaller parts using the modified multiplication algorithm. Here's an example implementation:
import java.util.Arrays;
public class LargeIntegerDivision {
public static void main(String[] args) {
String input = "123456789";
int n = input.length();
int nDiv3 = n/3;
String[] parts = new String[3];
parts[0] = input.substring(0, nDiv3);
parts[1] = input.substring(nDiv3, 2*nDiv3);
parts[2] = input.substring(2*nDiv3, n);
System.out.println("Divided parts: " + Arrays.toString(parts));
String result = multiplyParts(parts);
System.out.println("Result: " + result);
}
public static String multiplyParts(String[] parts) {
// Implement modified multiplication algorithm here
// Multiply the smaller parts
// Return the result
}
}