Final answer:
When conductor A and B touch each other, electrons are transferred from conductor A to conductor B. If the grounding wire is removed and the charged rod is removed after moving conductor B away from conductor A, the charges on both conductors will return to their original values. If the second ball (conductor B) is grounded while the rod is still near, it will lose its negative charge and become neutral.
Step-by-step explanation:
When conductor A and B touch each other, electrons are transferred from conductor A to conductor B. This results in conductor A losing some of its negative charge and becoming less negative, while conductor B gains those electrons and becomes more negative.
If the grounding wire is removed and conductor B is moved far away from conductor A before removing the charged rod, the two conductors will no longer have induced charges. The charges on conductor A and B will return to their original values of -5 nC and -3 nC, respectively.
If the second ball (conductor B) is momentarily grounded while the rod is still near, it will lose its negative charge to the ground, resulting in a neutral charge on conductor B.