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Passengers get on a train at the train station and the train begins moving from a standstill. The train eventually reaches a top speed of 30 km/hr as it underwent a constant acceleration of 1.3 m/s². How many seconds did it take the train to reach its top speed?

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Final answer:

It took approximately 6.41 seconds for the train to reach its top speed of 30 km/hr from a standstill with a constant acceleration of 1.3 m/s².

Step-by-step explanation:

The student wants to know how long it takes for the train to reach its top speed of 30 km/hr, given a constant acceleration of 1.3 m/s². To solve this problem, we'll use the formula for acceleration where acceleration (a) = change in velocity (Δv) / time (t).

First, we need to convert the top speed to meters per second since the acceleration is given in meters per second squared. So, 30 km/h converts to 30,000 m/3600 s ≈ 8.33 m/s. Now we know that the Δv = 8.33 m/s - 0 (since it started from rest), and a = 1.3 m/s². Using the formula, t = Δv / a, we get t = 8.33 m/s / 1.3 m/s² ≈ 6.41 seconds.

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