Final answer:
The speed of the slower car is 4.93827160 m/s after calculating the total distance covered by both cars in 3 hours and converting km/h to m/s.
Step-by-step explanation:
To solve this problem, we first need to establish the relationship between the speeds of the two cars and the total distance covered in 3 hours. Let's suppose the speed of the slower car is v km/h. Therefore, the speed of the faster car will be 2v km/h. Since they are traveling in opposite directions, after 3 hours, they will be 3v + 3(2v) = 160 km apart. Simplifying this, we get 9v = 160 km.
Dividing both sides by 9 to solve for v, we get v = 160 / 9 km/h. To convert this speed into m/s, we use the conversion factor 1 km/h = 1/3.6 m/s. Therefore, v = (160 / 9) / 3.6 m/s.
After performing the calculations, we find that the speed of the slower car is 4.93827160 m/s.