Final answer:
The question is about calculating the percent yield of oxygen in a chemical reaction, but the necessary data (theoretical yield) to perform this calculation is not provided, making it impossible to accurately answer the question with the given options.
Step-by-step explanation:
To calculate the percent yield of oxygen in the chemical reaction where 93.3 kg of PbO is reduced to yield 77.3 kg of pure lead, we would use the formula:
Percent Yield = (Actual Yield/Theoretical Yield) × 100.
We know the actual yield of lead is 77.3 kg, but the question does not provide us with the theoretical yield necessary to calculate the percent yield. Without this information, we cannot determine the percent yield of oxygen in the reaction. The percent yields provided as options (A) 69.63%, (B) 73.40%, (C) 90.82%, and (D) 136.2% cannot be directly linked to the reaction detailed without further information.