Final answer:
The shearing strain of the cube of aluminum is 0.00333.
Step-by-step explanation:
The question asks about the shearing deformation of a cube of aluminum subjected to a tangential force. The cube has a side length of 6 cm. The top of the cube is sheared through 0.02 cm with respect to the bottom. Shearing strain, also known as shear strain, represents the change in shape resulting from the application of a force parallel to a surface. Shearing stress, also known as shear stress, represents the force per unit area acting parallel to a surface.
To calculate the shearing strain, we use the formula:
Shearing Strain = Change in Length / Original Length
Given that the change in length is 0.02 cm and the original length is 6 cm, we can substitute the values to obtain:
Shearing Strain = 0.02 cm / 6 cm = 0.00333
To calculate the shearing stress, we use the formula:
Shearing Stress = Shear Force / Cross-sectional Area
Unfortunately, the given question does not provide the shear force or the cross-sectional area of the cube, so we cannot calculate the shearing stress using the information provided.