Question

Solve the system of equations below.x + y = 72x + 3y = 16 (5, 2) (2, 5) (3, 4) (4, 3)

Answer 1

Given,

The expression is:

`\begin{gathered} x+y=7 \\ 2x+3y=16 \end{gathered}`

Taking the first equation as,

`\begin{gathered} x+y=7 \\ x=7-y \end{gathered}`

Substituting the value of x in second equation.

`\begin{gathered} 2x+3y=16 \\ 2(7-y)+3y=16 \\ 14-2y+3y=16 \\ y=16-14 \\ y=2 \end{gathered}`

Substituting the value of y in first equation.

`\begin{gathered} x+y=7 \\ x+2=7 \\ x=5 \end{gathered}`

Hence, the solution of system of equation is (5, 2).