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2(r +5) = 7r3 (4d -3 ) = -2d + 5

User Nikhil Agarwal
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1 Answer

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20 votes

You have the following equations:

2(r +5) = 7r

3 (4d -3 ) = -2d + 5​

In order to solve the previous equations, proceed as follow:

2(r +5) = 7r apply distribution property

2r + 10 = 7r subtract 2r both sides

10 = 7r - 2r

10 = 5r divide by 5 both sides

10/5 = r

2 = r

r = 2

3 (4d -3 ) = -2d + 5​ apply distribution property

12d - 9 = -2d + 5 add 2d both sides

12d + 2d - 9 = 5 add 9 both sides

12d + 2d = 5 + 9 simplify both sides

14d = 14 divide by 14 both sides

d = 14/14

d = 1

Hence, the solutions to the given equations are r = 2 and d = 1

User Rafael Carvalho
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