Question

A tennis ball is hit with an initial velocity of 15 m/s at an

angle of 30°. What is the horizontal distance of the ball
after 2 seconds? (round to the nearest meter)
A. 12 m
B. Om
C. 30 m
D. 24 m

Answer 1

The horizontal distance of the ball after 2 seconds is approximately 26 meters.

Step-by-step explanation:

To find the horizontal distance of the ball after 2 seconds, we need to split the initial velocity into horizontal and vertical components. The horizontal component can be found by multiplying the initial velocity (15 m/s) by the cosine of the angle (30°). The vertical component can be found by multiplying the initial velocity (15 m/s) by the sine of the angle (30°).

The horizontal distance can then be calculated using the formula:

distance = horizontal velocity × time

Plugging in the known values, we have:

distance = (15 m/s × cos(30°)) × 2 s

Simplifying the equation, we get:

distance ≈ 26 m

Therefore, the horizontal distance of the ball after 2 seconds is approximately 26 meters.