Final answer:
The average velocity of a bicycle traveling 200 m in 38 s is 5.26 m/s. Among the four cyclists, Cyclist 4 has the greatest average speed of 4.50 m/s.
Step-by-step explanation:
To compute the average velocity of a bicycle that travels 200 m in 38 s, we can apply the formula v = d/t. Plugging in the values, we get:
v = 200 m / 38 s = 5.26 m/s (to two decimal places).
Now, to determine which cyclist traveled with the greatest average speed out of the four given options, we need to calculate the average speed for each cyclist. The one with the highest value will have the greatest average speed.
- Cyclist 1: v = 95 m / 27 s = 3.52 m/s
- Cyclist 2: v = 87 m / 22 s = 3.95 m/s
- Cyclist 3: v = 106 m / 26 s = 4.08 m/s
- Cyclist 4: v = 108 m / 24 s = 4.50 m/s
From the above calculations, we can see that Cyclist 4 has the highest average speed at 4.50 m/s.