72.8k views
3 votes
Write down the polynomial that has the following:

A degree of 2, constant of 3, linear coefficient of - 2, and leading coefficient of 12.

User Lelo
by
7.6k points

1 Answer

4 votes

Final answer:

The polynomial with a degree of 2, a leading coefficient of 12, a linear coefficient of -2, and a constant of 3 is 12x² - 2x + 3 = 0.

Step-by-step explanation:

The student is asking for a polynomial with specific coefficients and degree. To write down this polynomial, we need to arrange the terms with the given coefficients and constant into the standard form of a quadratic equation, which is ax² + bx + c = 0. Here, the leading coefficient a is 12, the linear coefficient b is -2, and the constant c is 3.

The resulting polynomial with the given conditions would be: 12x² - 2x + 3 = 0.

This quadratic polynomial has a degree of 2, satisfying the requirement. Remember that the degree of a polynomial is determined by the highest power of the variable x that appears in the equation.

User Zzzgoo
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.