Question

Solve.

A. 3a + 3b + c = - 33
B. a-3b + 2c = -1
C. 8a - 2b + 3c = - 40

What is the solution?

Answer 1

The solution to the given system of equations is a = 5/3, b = -5/3, and c = -4/3.

Step-by-step explanation:

The solution to the given equations is obtained by using the method of substitution or elimination. Here is the step-by-step solution:

1. Start with the first equation: 3a + 3b + c = -33
2. Next, substitute the values of a, b, and c from the second equation: a - 3b + 2c = -1. Substitute a = 3b - 2c - 1
3. Now, substitute the values of a and c from the third equation: 8a - 2b + 3c = -40. Substitute a = 3b - 2c - 1 and c = -6b + 4
4. Simplify the equation and solve for b. Substituting the values of b and c, we get: 63b - 45 = -40
5. Solve for b: b = -5/3
6. Substitute the value of b back into the equations to find the values of a and c: a = 5/3 and c = -4/3

Therefore, the solution to the given system of equations is a = 5/3, b = -5/3, and c = -4/3.