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Solve using u for all possible values of x. Use the complete the square method if possible.

x⁴-13x²+36=0

1 Answer

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Final answer:

The equation x⁴ - 13x² + 36 = 0 can be solved using the complete the square method. The possible values of x are -3, 3, -2, and 2.

Step-by-step explanation:

This equation can be solved using the complete the square method. Let's begin:

x⁴ - 13x² + 36 = 0

First, let's rewrite the equation as a quadratic expression:

(x²)² - 13x² + 36 = 0

Now, let's complete the square by adding and subtracting the square of half the coefficient of x²:

(x²)² - 13x² + ({{-13/2}})² - ({{-13/2}})² + 36 = 0

Simplifying, we get:

(x² - 6.5)² - 42.25 + 36 = 0

Combining like terms, we have:

(x² - 6.5)² - 6.25 = 0

Now, let's solve for x:

(x² - 6.5)² = 6.25

Taking the square root of both sides, we get:

x² - 6.5 = ±√6.25

x² - 6.5 = ±2.5

Solving for x, we have two cases:

Case 1: x² - 6.5 = 2.5

x² = 9

x = ±3

Case 2: x² - 6.5 = -2.5

x² = 4

x = ±2

So, the possible values of x are x = -3, x = 3, x = -2, and x = 2.

User Jonathan DS
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