Final answer:
The volume of a sample of neon at STP, given its initial conditions at 25°C and 800 mm Hg, can be calculated using the combined gas law. The result is that the volume of the neon gas at STP would be 863 liters.
Step-by-step explanation:
To calculate the volume of a sample of neon at STP (standard temperature and pressure), which is defined as 0°C and 1 atm pressure, we can use the combined gas law, given that the initial conditions are 25°C (which is 298 K when converted to Kelvin) and 800 mm Hg pressure, with an initial volume of 900 L.
The combined gas law is given by:
\(\frac{P1 × V1}{T1} = \frac{P2 × V2}{T2}\)
First, we convert the pressure from mm Hg to atm, knowing that 1 atm = 760 mm Hg:
\(800 \text{ mm Hg} × \frac{1 \text{ atm}}{760 \text{ mm Hg}} = 1.053 \text{ atm}\)
Now we can plug in the values into the combined gas law:
\(\frac{1.053 \text{ atm} × 900 \text{ L}}{298 \text{ K}} = \frac{1 \text{ atm} × V2}{273 \text{ K}}\)
Solving for \(V2\), we get:
\(V2 = \frac{1.053 \text{ atm} × 900 \text{ L} × 273 \text{ K}}{1 \text{ atm} × 298 \text{ K}}\)
\(V2 = \frac{256977 \text{ L}·\text{K}}{298 \text{ K}}\)
\(V2 = 863 L\)
Therefore, the volume of the neon gas at STP would be 863 liters.