Question

A trick or treater walks from the door of one house back to her house 250 m north, then turns 90º to the right and walks an additional 60 m to hide her candy in the woods.

a. What is the total distance walked?

Answer 1

The total distance walked by the trick or treater is 310 meters, which is calculated by adding the distances from the two parts of the walk: 250 meters north and 60 meters east.

Step-by-step explanation:

The total distance walked by the trick or treater who first moves 250 m north and then turns 90º to the right to walk an additional 60 m is simply the sum of the two distances. To find the total distance, we add the distance from the first and second leg of the walk.

The trick or treater walks 250 m north and then 60 m in a direction that is 90º to the right of north, which we can assume to be east. The total distance walked is the sum of these two values:

• First leg (north): 250 m
• Second leg (east): 60 m

The total distance walked is:

1. 250 m (north) + 60 m (east) = 310 m

Therefore, the trick or treater walks a total distance of 310 meters.