Final answer:
The question is about calculating the volume of a 0.075 M potassium hydroxide solution that contains 39 grams of KOH. By using the molarity formula and the molar mass of KOH, we can find the moles of KOH and subsequently the volume of the solution.
Step-by-step explanation:
The question seems to have a typo as it refers to '0.075 M sodium' but mentions 'potassium hydroxide (KOH)'. Assuming the intention was to inquire about the volume of a 0.075 M KOH solution that contains 39 grams of KOH, we can use the formula:
molarity (M) = moles of solute / volume of solution in liters
First, calculate the moles of KOH by using its molar mass (approximately 56.11 g/mol).
Moles of KOH = mass (g) / molar mass (g/mol)
Moles of KOH = 39 g / 56.11 g/mol
Now, rearrange the molarity formula to solve for the volume:
Volume of solution (L) = moles of solute / molarity (M)
Insert the moles calculated and the given molarity to find the volume.