Question

It is now exactly 10:29 am. Suzette is trying to get to French class before the tardy bell rings at 10:30 am. If she doesn't make it on time, it will be her third tardy this week. She must get from the other side of the building to the French classroom by hurrying down three different hallways. She runs down the first hallway, a distance of 35 meters at 3.5 m/s. The second hallway is full of students, she covers the 48 meter length at a speed 1.2 m/s. The third hallway is empty and she sprints down it's 60.0 meter length at 5.00 m/s. What is suzettes average speed for the run to class?

Answer 1

Suzette's average speed for her run to the French class, after covering distances of 35 meters, 48 meters, and 60 meters at varying speeds, was approximately 2.31 m/s.

Step-by-step explanation:

To find Suzette's average speed for her entire run to the French class, we need to consider the total distance she ran and the total time she took to run that distance. She ran three hallways with lengths of 35 meters, 48 meters, and 60.0 meters at speeds of 3.5 m/s, 1.2 m/s, and 5.00 m/s, respectively. First, we calculate the time taken to run each hallway:

• Time for first hallway: 35 meters / 3.5 m/s = 10 seconds.
• Time for second hallway: 48 meters / 1.2 m/s = 40 seconds.
• Time for third hallway: 60.0 meters / 5.00 m/s = 12 seconds.

Next, we combine these times to obtain the total time:

Total time = 10 seconds + 40 seconds + 12 seconds = 62 seconds.

And the total distance:

Total distance = 35 meters + 48 meters + 60 meters = 143 meters.

Finally, we calculate Suzette's average speed:

Average speed = Total distance / Total time = 143 meters / 62 seconds ≈ 2.31 m/s.

Therefore, Suzette's average speed for the run to her French class was approximately 2.31 m/s.