Question

Evaluate the algebraic expression below for:

S = 2, t = -3
2s² – t³/⁹

O A) 11
O B) 5
O C) -19/9
O D) 9

Answer 1

The quadratic equation t² + 10t - 200 = 0 can be solved using the quadratic formula, yielding two solutions: t = 10 and t = -20.

Step-by-step explanation:

To solve for t using the quadratic formula in the equation t² + 10t - 200 = 0, first we need to identify the coefficients a, b, and c from the standard form of a quadratic equation at² + bt + c = 0. Here, a = 1, b = 10, and c = -200. Applying the quadratic formula, -b ± √b² - 4ac / 2a, we plug in the values for a, b, and c:

t = (-10 ± √(10² - 4×1×-200)) / (2×1)

t = (-10 ± √(100 + 800)) / 2

t = (-10 ± √900) / 2

t = (-10 ± 30) / 2

Thus, we have two possible solutions for t:

• t = (20) / 2 = 10
• t = (-40) / 2 = -20

Therefore, the two solutions are t = 10 and t = -20.