Question

A)Slope intercept form B) linear equationC)I am stuck on this half of my homework

Answer 1

Step-by-step explanation:

The points given in the question is given below as

`\begin{gathered} (46,368)=(x_1.y_1) \\ (64,422)=(x_2,y_2 \end{gathered}`

To figure out the equation of the line, we will use the formula below

`(y_2-y_1)/(x_2-x_1)=(y-y_1)/(x-x_1)`

By substituting the values, we will have

`\begin{gathered} (y_(2)-y_(1))/(x_(2)-x_(1))=(y-y_(1))/(x-x_(1)) \\ (422-368)/(64-46)=(y-368)/(x-46) \\ (54)/(18)=(y-368)/(x-46) \\ y-368=3(x-46) \\ y-368=3x-138 \\ y=3x-138+368 \\ y=3x+230 \end{gathered}`

Hence,

The equation of the line in slope intercept form is

`y=3x+230`

Part B:

To figure out the number of calories for 52.4 grams, we will use the formula above

Put x=52.4

`\begin{gathered} y=3x+230 \\ y=3(52.4)+230 \\ y=157.2+230 \\ y=387.2 \end{gathered}`

Hence,

The number of calories for 52.4grams will be

`387.2calories`

Part C:

Hence,

From the slope above in part a

If the weight of the candy bar is increased by 1 gram ,the number of calories will increase by 3 calories