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Given t(x) =− 4.9t2 + 3t + 10 , what is the value of t(1) ?

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Final answer:

To calculate t(1), substitute 1 into the function t(x) = -4.9t^2 + 3t + 10 and perform the arithmetic operations to arrive at the result, which is 8.1.

Step-by-step explanation:

To find the value of t(1), we need to substitute t = 1 into the function t(x) = -4.9t2 + 3t + 10. Let's do this step by step:

  • Substitute t = 1 into the equation: -4.9(1)2 + 3(1) + 10.
  • Simplify the squared term: -4.9(1) + 3 + 10.
  • Multiply -4.9 by 1: -4.9 + 3 + 10.
  • Add the numbers together: (-4.9 + 3) + 10 = -1.9 + 10.
  • Finally, calculate the sum: 10 - 1.9 = 8.1.

Therefore, the value of t(1) is 8.1.

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