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Given the following measurements, calculate the minimum and maximum possible areas of the object. Round your answer to the nearest whole square unit. Chris is painting a wall with a length of 3 meters and a width of 22 meters. The minimum possible area is about m2.

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Final answer:

The minimum and maximum areas of the wall to be painted by Chris, considering measurement uncertainties, are both approximately 12 square meters when rounded to the nearest whole unit.

Step-by-step explanation:

To calculate the minimum and maximum possible areas of a rectangular object like a room, you simply multiply the length by the width. However, when we have uncertainties in measurements, we need to consider them to find the range of possible areas. In the given measurements, the length is 3.955 ± 0.005 m and the width is 3.050 ± 0.005 m.

The maximum possible area occurs when both the length and the width are at their maximum values:

  • Length: 3.955 m + 0.005 m = 3.960 m
  • Width: 3.050 m + 0.005 m = 3.055 m

The minimum possible area occurs when both the length and the width are at their minimum values:

  • Length: 3.955 m - 0.005 m = 3.950 m
  • Width: 3.050 m - 0.005 m = 3.045 m

Now we calculate the maximum and minimum areas:

  • Maximum area = 3.960 m * 3.055 m = 12.1058 m²
  • Minimum area = 3.950 m * 3.045 m = 12.03225 m²

When rounding to the nearest whole square unit, the maximum area is approximately 12 m² and the minimum area is approximately 12 m².

User Dan Zawadzki
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