Final answer:
The bug was traveling at a speed of approximately 16.27 cm/s along the edge of the circular planter.
Step-by-step explanation:
To find the speed of the bug traveling along the edge of a circular planter, we can use the equation v = rω, where v is the speed, r is the radius, and ω is the angular velocity. First, we need to find the angular velocity using the equation ω = θ/t, where θ is the angle and t is the time taken. In this case, the bug completes one lap, which is equivalent to 2π radians, in a time of 8.044 seconds. So, the angular velocity is ω = (2π radians) / (8.044 seconds).
Next, we can substitute the values into the equation v = rω. The radius of the planter is given as 20.8 cm, so the speed of the bug traveling along the edge of the planter is v = (20.8 cm) × ((2π radians) / (8.044 seconds)).
Now we can calculate the numerical value of the speed by converting the units. The speed would be (20.8 cm) × ((2π radians) / (8.044 seconds)) = (20.8 cm) × (0.7843 rad/s) ≈ 16.27 cm/s.