Final answer:
During the electrolysis of copper sulfate, 0.29 grams of copper were deposited on the cathode.
Step-by-step explanation:
The question involves the calculation of the amount of copper deposited on the cathode during the electrolysis of copper sulfate using copper electrodes. The initial mass of the cathode is given as 1.28g and the final mass after electrolysis is 1.57g. To find the mass of the copper deposited, we subtract the initial mass of the cathode from the final mass:
Mass of copper deposited = Final mass of cathode - Initial mass of cathode
Mass of copper deposited = 1.57g - 1.28g = 0.29g
Thus, 0.29 grams of copper were deposited on the cathode during the 5 minutes of electrolysis.