Question

A farmer collects data on how many days it takes an orange to grow from a bud to a full fruit. The data is normally distributed with a mean of 17 day and a standard deviation of 1.1 days. What would be the score for an orange that takes 19 daya to fully grow?

Answer 1

The z-score for an orange that takes 19 days to fully grow, with a mean of 17 days and a standard deviation of 1.1 days, is approximately 1.82.

Step-by-step explanation:

The question asks to find the z-score for an orange that takes 19 days to grow given that the mean growth time is 17 days with a standard deviation of 1.1 days. To calculate the z-score, we use the formula z = (X - μ) / σ, where X is the value of interest, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z = (19 - 17) / 1.1, which simplifies to z = 2 / 1.1. This yields a z-score of approximately 1.82.