Final answer:
The probability of selecting a defective roll followed by another defective roll is 1/15 or approximately 0.07.
Step-by-step explanation:
To determine the probability of selecting a defective roll followed by another defective roll, we need to consider the total number of rolls and the number of defective rolls. There are 10 rolls in total and 3 of them are defective.
For the first roll, the probability of selecting a defective roll is 3/10 (3 defective rolls out of 10 total rolls).
For the second roll, since one roll has already been selected and not replaced, there are now 9 rolls left and 2 of them are defective. Therefore, the probability of selecting another defective roll is 2/9.
To find the probability of both events occurring, we multiply the probabilities together:
P(defective roll followed by another defective roll) = (3/10) * (2/9) = 6/90 = 1/15 approximately 0.07