Question

kevin and randy muise have a jar containing 71 coins, all of which are either quarters or nickels. the total value of the coins in the jar is $10.15. how many of each type of coin do they have?

Answer 1

The problem is solved by setting up two equations based on the total number of coins and their total value, and then solving for the number of quarters and nickels using algebraic methods such as substitution or elimination.

Step-by-step explanation:

The question is about determining the number of quarters and nickels in a jar that collectively amount to $10.15 with a total of 71 coins involved. We define two variables: let q be the number of quarters and n be the number of nickiles. We have two equations based on the problem statement:
q + n = 71 (total number of coins)
0.25q + 0.05n = 10.15 (total value in dollars).

We can solve these equations using the substitution or elimination method. By rearranging the first equation we get n = 71 - q, and then we substitute it into the second equation:
0.25q + 0.05(71 - q) = 10.15. Solving for q we find the number of quarters, and we can use that to find n, the number of nickels.