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A 14-kg medicine ball is thrown at a velocity of 5m/s to a 73-kg person who is at rest on ice. The person catches the ball and subsequently slides with the ball across the ice. What is the speed of the person and ball after the collision?

User Elliot Fehr
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1 Answer

10 votes
10 votes

We will have the following:

First, we will solve using the conservation of momentum:


\begin{gathered} (14kg)(5m/s)+(73kg)(0m/s)=(14kg+73kg)v \\ \\ \Rightarrow70N\ast m=87kg\ast v\Rightarrow v=(70kg\ast m/s)/(87kg) \\ \\ \Rightarrow v=(70)/(87)m/s\Rightarrow v\approx0.8m/s \end{gathered}

So, the final velocity will be approximately 0.8 m/s.

User Taz
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