Question

Alain throws a stone off a bridge into a river. The stone's height in meters over the water x seconds after Alain throws it is modeled by H(x) = 5x^2 + 10x + 15. What is the height of the stone at the time it is thrown?

Answer 1

The height of the stone at the time it is thrown is found by evaluating H(x) at x=0 seconds, which results in the initial height of 15 meters above the water.

Step-by-step explanation:

The height of the stone at the time it is thrown can be determined by evaluating the function H(x) for the stone's height at the initial time, which is when x = 0 seconds. By substituting x = 0 into the equation H(x) = 5x^2 + 10x + 15, the initial height H(0) can be calculated.

Let's evaluate the function:

• H(0) = 5(0)^2 + 10(0) + 15
• H(0) = 0 + 0 + 15
• H(0) = 15 meters

Therefore, the height of the stone at the time it is thrown is 15 meters above the water.