Final answer:
The maximum amount of CaCO₃ that could be produced from the given reactants is 1.375 moles due to HCl being the limiting reactant. The mass of FeCl₃ produced would be 148.76 grams.
Step-by-step explanation:
To determine how many moles of CaCO₃ would be produced from the given reactants in the balanced chemical equation, we first need to identify the limiting reactant which will dictate the maximum amount of product formed. The balanced equation is 6 HCl + Fe₂(CO₃)₃ + 3 Ca(OH)₂ → 2 FeCl₃ + 3 CaCO₃ + 6 H₂O. Based on the molar ratios, 0.7 moles of Fe₂(CO₃)₃ would theoretically produce 3×0.7/1 = 2.1 moles of CaCO₃. However, the reaction also requires 6 moles of HCl and 3 moles of Ca(OH)₂ for every mole of Fe₂(CO₃)₃. Given only 2.75 moles of HCl are available, this will be the limiting reactant. The amount of CaCO₃ that can be produced in this case will be 3×2.75/6 = 1.375 moles.
To find out the mass of FeCl₃ produced, we use the molar mass of FeCl₃ (162.2 g/mol) and the number of moles of FeCl₃ formed from the limiting reactant, which is 2×2.75/6 = 0.917 moles. Therefore, the mass of FeCl₃ produced will be 0.917 moles × 162.2 g/mol = 148.76 grams.