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Carmen, Milan, and Ryan have a total of $74 in their wallets. Milan has 3 times what Ryan has. Ryan has $6 more than Carmen. How much do they have in their wallets?

A. Carmen: $22, Milan: $66, Ryan: $18
B. Carmen: $26, Milan: $30, Ryan: $18
C. Carmen: $24, Milan: $36, Ryan: $14
D. Carmen: $20, Milan: $60, Ryan: $14

User ESniff
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1 Answer

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Final answer:

After setting up and solving a system of equations based on the information provided, we find that Carmen has $10, Ryan has $16, and Milan has $48. This sums up to the total amount of $74 they collectively have in their wallets, which doesn't match any of the given options, indicating an issue with the question or the choices provided.

Step-by-step explanation:

To determine how much money Carmen, Milan, and Ryan have in their wallets, we need to set up a system of equations based on the information given:

  1. Carmen, Milan, and Ryan have a total of $74.
  2. Milan has 3 times what Ryan has.
  3. Ryan has $6 more than Carmen.

Let's denote the amount of money Carmen has as C, Milan as M, and Ryan as R.

Based on the information:

  • M = 3R (Milan has 3 times what Ryan has)
  • R = C + $6 (Ryan has $6 more than Carmen)
  • C + M + R = $74 (The total amount they have)

We substitute M and R from the first two equations into the third equation:

C + 3R + R = $74

C + 4R = $74

Because R = C + $6, we can substitute C + $6 in place of R:

C + 4(C + $6) = $74

Now, we solve for C:

C + 4C + $24 = $74

5C + $24 = $74

5C = $50

C = $10

Now that we know Carmen has $10, we can find out what Ryan has:

R = C + $6 = $10 + $6 = $16

And Milan's amount is 3 times Ryan's:

M = 3R = 3 × $16 = $48

Let's verify the total:

C + M + R = $10 + $48 + $16 = $74

The correct answer matches none of the provided options, suggesting a possible error in the question or the options given.

User GIRISH Kuniyal
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