105k views
5 votes
What does 2x^2 - 50 = x^2 + 1 solve this quadratic function by factoring?

A) x = 7.
B) x = -7.
C) x = 6.
D) x = -6.

User Skubski
by
8.5k points

1 Answer

3 votes

Final answer:

To solve the quadratic equation 2x^2 - 50 = x^2 + 1 by factoring, rearrange the equation, factor it, and solve for x. The solutions are x = 7 and x = -7.

Step-by-step explanation:

To solve the quadratic equation 2x^2 - 50 = x^2 + 1 by factoring, we first rearrange the equation to have 0 on one side: 2x^2 - 51 = x^2. Then, we combine like terms and set the equation equal to 0: x^2 - 51 = 0. Next, we factor the equation as (x - 7)(x + 7) = 0. Setting each factor equal to 0, we find two possible solutions: x - 7 = 0 and x + 7 = 0. Solving for x, we get x = 7 and x = -7.

User Mchasles
by
7.4k points