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What is the standard form equation for a 1/2 line that passes though (-3,-3) and (4,2)

User Ephedra
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1 Answer

9 votes

Answer:

y= 5/7x -2.7

Explanation:

Y= mx + c (-3,-3) (4,2)

x1 , y1 x2, y2

to find m (gradient)

y^2 - y^1 / x^2 - x^1

2-(-3) / 4 - (-3)

5/7 m = 5/7

take (4,2) and gradient and substitute

2=5/7(4) + c

2=4.7+ c

2-4.7 = c

-2.7 = c

now we have c and m so just put it in the equation

y= 5/7x -2.7

User Ia
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