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A constant friction force of 21 N acts on a 63-kg skier for 25 s on level snow. What is the skier’s change in velocity?

1 Answer

9 votes
The skier’s change in velocity is 8.33.../8.4 m/s.
21/63= 0.33...
0.33...x 25 s = 8.33.../8.4 m/s
User Sytolk
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